Entering this season with very high expectations, a good start in it was an end in itself for Portsmouth in its attempt to go one step further this year and that is exactly what it achieved in the premiere, beating Luton in Fratton 1-0. An ideal start for the team of the experienced Kenny Jacket, which also has one of the heaviest jerseys in the category and which, we remind you, is considered by the betting companies as the third favorite to rise behind Sunderland and Barnsley, both from of the three that came from the Championship.
On the other side, things in Blackpool are not as rosy, with the main reason of course the many administrative problems that have plagued the team for years now. As they swell instead of shrink, the climate and the situation in general will remain ... wrong and to understand the magnitude of the problem, suffice it to say that her coach, Gary Boyer, resigned during the week, just in the first week of the new season.
As for its premiere, it started with a white tie at the headquarters of the newly enlightened Wycombe and although the result can be considered positive, the same cannot be said for her appearance. Especially from the center and in front, he threatened little (however, he had, to say it all, a crossbar in the first half) revealing the lack of quality that exists in this field, defensively he did not get a good grade since he kept the zero but in that he probably helped a lot and Wycombe's highly predictable game, which was content mainly with crosses looking for Aquinas. With Portsmouth playing with the ball down, as we say, my feeling is that the test for Blackpool defense will be much more difficult.
In conclusion, my bet will go to double of 2,61 offered by goalbet. I would not characterize it as a super opportunity, but I consider it to be a very, if not very honest honor for Portsmouth, which is the logical favorite anyway, especially with what is happening in the opposing camp. At 2,35-2,40 I was calculating the double, so I believe that there is at least a nugget of value.