Simple combination system

Mr George, thank you very much for your time in writing us all the probabilities. We appreciate your knowledge we recognize them. We do not consider your proposal to be a point of contention - please play and 3 double chances do not matter - and that too you are showing great weight, in this case only in basketball while we are looking for only 1 race, as far as possible, in any sport, with low risk, which shows that we have a high probability of being certain we played back and continued to win.
In order to avoid any misunderstanding and not to appear to be misleading anyone we write the following results for all 5 times
1. 2,26 and 4 under 28,95
2.1,35 and 3 over and 2 under 19,49
3.1,13-1,15-1,20 and 5 over 13,77
4.1,10-1,12-1,14 and 4 handicaps 10,42
5.1,42 and 5 under 31,26
Hoping that with a simple addition everyone can come to their conclusions, thank you again.
The analysis was clear for 5 doubles matches (and not just basketball) and it really loses the system.
And you write when in 500 games you can't find a match of 1

I'm not looking for games at 1,40 but like the bottom and not at 1,40

If you have patience and you know the way to win and with accurate scores
Hint is 0-1 goals (special bets) but 1-0 score in 13 games 11 have accurate score 1-0 if you did not score accurate 1-0 but 1 + under
then 13 out of 13 !!

1577095023538.png


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The analysis was clear for 5 doubles matches (and not just basketball) and it really loses the system.
And you write when in 500 games you can't find a match of 1

I'm not looking for games at 1,40 but like the bottom and not at 1,40

If you have patience and you know the way to win and with accurate scores
Hint is 0-1 goals (special bets) but 1-0 score in 13 games 11 have accurate score 1-0 if you did not score accurate 1-0 but 1 + under
then 13 out of 13 !!

1577095023538.png


Reactions:summi, SERRES, stxma and 1 other user

V


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Good evening to all
if you can tell me how this system is played please
do I play it in two cards with the one guy, the other over in the other two with my 1.12 three games and ask for two or three standard 1.12 games?
thank you very much
 
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Your opinion is useful



Friend
stevakos
I have to tell you that we are playing on the internet to avoid too many tickets and in the event of an error. You are racing 1 over 2 with 1 over 3 with 1 and then 4,1-5,2-3,2-4,2 -5,3-4,3-5,4-5-20 and you precisely do it with the under.In the end you put the races on my first post, on the front page, with the width you see AND in the 3 columns Choosing ONLY a team of 3. If you find it difficult to find 2 races, you run 1,20 of 1,40 or only 5, whatever else you believe most. 3. Let's note something else .You can play whatever you want the NBA with NCAA with EUROLEAGUE etc. And below any sport you want. 4st to 4nd or 3rd races because we are based there and 1.Read the comments of other friends here and learn ...
 
I never talked with 5 doubles that you have 32 pairs.

1. you play under 1.90 andi over 1.90 5 matches for 100% doubles columns 20. Right?


2. Analysis of all cases and their percentages with the 20 columns



3.The probability for the 5 duplicate columns is 32 and 100/32 = 3,125% each column.

.
George Triantafillou

Mr George, number 3 is written .....
(3.The probability for the 5 duplicate columns is 32 and 100/32 = 3,125% each column.)

and, number 2 reads ..... (2. Analysis of all cases and their percentages with 20 columns)
!!
 
Friend
stevakos
I have to tell you that we are playing on the internet to avoid too many tickets and in the event of an error. You are racing 1 over 2 with 1 over 3 with 1 and then 4,1-5,2-3,2-4,2 -5,3-4,3-5,4-5-20 and you precisely do it with the under.In the end you put the races on my first post, on the front page, with the width you see AND in the 3 columns Choosing ONLY a team of 3. If you find it difficult to find 2 races, you run 1,20 of 1,40 or only 5, whatever else you believe most. 3. Let's note something else .You can play whatever you want the NBA with NCAA with EUROLEAGUE etc. And below any sport you want. 4st to 4nd or 3rd races because we are based there and 1.Read the comments of other friends here and learn ...

thanks a lot for explaining my buddy ... i think i have it now!
 
Mr George, number 3 is written .....
(3.The probability for the 5 duplicate columns is 32 and 100/32 = 3,125% each column.)

and, number 2 reads ..... (2. Analysis of all cases and their percentages with 20 columns)
!!
Good morning.
The 5 duplicates are 32 columns right?
1.The under under odds are at 1,90 - 1,90 which means they have the same chance of coming.
2. The 5 double columns are 32 and the probability of each column coming up is 100/32 = 3,125%
3. Requesting duplicates of 5 duplicates producing duplicates of the complete duplicate system of 5 duplicates
and gives us 20 columns in binaries ie 10 columns with under binaries and 10 columns with over binaries correctly?
4. If you sort and come up with a 5 under column is one of 32 that gives us 10 binaries but
the probability of it coming is only 3,125% The same odds if it comes 5 over and gives us 10 doubles
5. If in 5 races we have 4 under +1 over then we have 100% 6 doubles and probability is 5X3,125 = 15,625%
We get the same result if we have 4 over + 1 under 100% 6 bits and the probability is 5X3,125 = 15,625%
6. If we have 2 under + 3 over or 3 over + 2 under gives the system 100% 4 doubles and the odds
is 20 columns X 3,125 = 62,25%
7. When sorting, make a 5-point under -over column of 32 or you can sort
and 32 columns to see how many pairs each case gives.
I can't do better than that.
Hope dear stxma to solve your queries
 
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Very nice food for thought, but my question is the following (Silver said earlier): from playing € 40 to triplets or quadruplets or fifties that will bring in at least € 10 sure, provided we catch all three match of 1,12 or two of 1,20 or one of 1,40, why not play 40 € in three matches of 1,12 or two of 1,20 or one of 1,40? So, with the same assumption as before, you make at least 16 € profit and you save the hassle of many tickets!

Correct me if I'm doing something wrong ..
 
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Very nice food for thought, but my question is the following (Silver said earlier): from playing € 40 to triplets or quadruplets or fifties that will bring in at least € 10 sure, provided we catch all three match of 1,12 or two of 1,20 or one of 1,40, why not play 40 € in three matches of 1,12 or two of 1,20 or one of 1,40? So, with the same assumption as before, you make at least 16 € profit and you save the hassle of many tickets!

Correct me if I'm doing something wrong ..


We also feel it is right on our part to write our final results
1. defeat of Real -20
2. Al Jazeera win 3,35 with 3 under and 2 over 28,37
3. Exeter wins 1,55 and 4 under 13,57
4. 1,14-1,16-1,15 and 4 under 12,88
5.1,20-1,20-1,04 and 3 over and 2 under 1,62
6.1,33-1,36 and 4 over 19,17
Thanks.
 
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Good evening to me too !!
The ones I understand and the ones I know are:

1. The probability of an overflow coming is 0.5
2. The probability of coming in 'a double' is 0.25
3. So the probability of a 5 round in 5 rounds is equal to 0.03125 (0.5x0.5x0.5x0.5x0.5)
4. Playing 5 points of full growth we have:
-5/32 chance of catching 1 overs
-10/32 chance of catching 2 overs
-10/32 chance of catching 3 overs
-5/32 chance of catching 4 overs
-1/32 chance of catching 5 overs
-1/32 chance of not catching any overs
5. If 5 overs come we have 10/10 doubles
6. If 4 overs come we have 6/10 doubles
7. If 3 overs come we have 3/10 doubles
8. If 2 overs come in we have 1 / 10ths
9. Overall we have 1/32 odds for 10/10 doubles + 10/32 odds for 6/10 doubles + 10/32 odds for 3/10 doubles
9. Summarizing:
-0.03125 probability of coming 5 days
- (10x0.03125) 0.3125 chance of coming 4 weeks
- (10x0.03125) 0.3125 chance of coming 3 weeks
a total of 0.65625
10. So we have (1 + 10 + 10) 21/32 odds
11. Playing only 1 € per column in odds 1.9 so 10 € total cost of twin tickets we have:
1/32 chance of getting 1.9x1.9x10 = 36.1 €
10/32 chance of getting 1.9x1.9x6 = 21.66 €
10/32 chance of getting 1.9x1.9x3 = 10.83 €
12. If we play now and the respective men we have 1/32 chance of getting a couple of the 3s we won earlier with a total odds of (0.65625 + 0.03125) 0.6875 but at a cost of 20 €
13. So we get 3 pairs and a couple of opposites.
14. Final conclusion:
With a total probability of 0.6875 we have
Ή (1.9x1.9x10) -20 = 16.1 € profit with 0.0625
Ή (1.9x1.9x6) -20 = 1.6 € profit with 0.3125
Ή {1.9x1.9x (3 + 1) -20} = -5.6 gaps with 0.3125
15. That's why our friend adds another 1.4 standard race to cover the rake !!! So that with 3 overs and one male will have {1.9x1.9x1.4x (3 + 1) -20} = 0.216 € profit
Whenever in his money the profit of 10.324 € or the profit of 22.54 €

Sorry for the big post !!
I hope I helped!!
Also if I had found a system to make money off the bet I would have shared it with the whole world !! I can't understand why such a negative action !!! From your pocket we will take them ????
Tinks
 
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We also feel it is right on our part to write our final results
1. defeat of Real -20
2. Al Jazeera win 3,35 with 3 under and 2 over 28,37
3. Exeter wins 1,55 and 4 under 13,57
4. 1,14-1,16-1,15 and 4 under 12,88
5.1,20-1,20-1,04 and 3 over and 2 under 1,62
6.1,33-1,36 and 4 over 19,17
Thanks.
I didn't understand what you are answering me, but ok, thanks.

Sent from my SM-G928F using Tapatalk
 
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Good morning.
The 5 duplicates are 32 columns right?
1.The under under odds are at 1,90 - 1,90 which means they have the same chance of coming.
2. The 5 double columns are 32 and the probability of each column coming up is 100/32 = 3,125%
3. Requesting duplicates of 5 duplicates producing duplicates of the complete duplicate system of 5 duplicates
and gives us 20 columns in binaries ie 10 columns with under binaries and 10 columns with over binaries correctly?
4. If you sort and come up with a 5 under column is one of 32 that gives us 10 binaries but
the probability of it coming is only 3,125% The same odds if it comes 5 over and gives us 10 doubles
5. If in 5 races we have 4 under +1 over then we have 100% 6 doubles and probability is 5X3,125 = 15,625%
We get the same result if we have 4 over + 1 under 100% 6 bits and the probability is 5X3,125 = 15,625%
6. If we have 2 under + 3 over or 3 over + 2 under gives the system 100% 4 doubles and the odds
is 20 columns X 3,125 = 62,25%
7. When sorting, make a 5-point under -over column of 32 or you can sort
and 32 columns to see how many pairs each case gives.
I can't do better than that.
Hope dear stxma to solve your queries
I see it again differently, and divide it into 3 probabilities

5-5 ..................... = 2 columns

4-1&1-4.............=10 στηλες

3-2&2-3.............=20 στηλες

Where it doesn't matter which of the 20 will come up, wherever we come in, we want a breakdown of the 3 cases. Whenever I say 33,33% each time.
 
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I see it again differently, and divide it into 3 probabilities

5-5 ..................... = 2 columns

4-1&1-4.............=10 στηλες

3-2&2-3.............=20 στηλες

Where it doesn't matter which of the 20 will come up, wherever we come in, we want a breakdown of the 3 cases. Whenever I say 33,33% each time.
Strongly Agree!! But:
33,33% probability of earning 16,1 €
33,33% probability of earning 1,66 €
33,33% probability of a slash -5,6 €
I'm trying to figure out if it's worth it !!
 
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Neither math nor betting. With your logical plane you have a 50% chance of falling.
It's not a matter of logic .. it's a matter of probability .. we're always talking about equally random possibilities of a sample space X consisting of two possibilities !! A and B.
A will come B or B .. the plane is made to fly not to fall .. so are two non-equilibrium events .. but it falls .. but with a probability frequency of minimum to zero ..
 
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I see it again differently, and divide it into 3 probabilities

5-5 ..................... = 2 columns

4-1&1-4.............=10 στηλες

3-2&2-3.............=20 στηλες

Where it doesn't matter which of the 20 will come up, wherever we come in, we want a breakdown of the 3 cases. Whenever I say 33,33% each time.

When have two columns? 33,33% probability why not have the other couples?
XXX (where X = UNDER)
11111 (where 1 = OVER) 5 under + over probability 33,33%
then with your own reason why we don't have 33,33% in both columns
11XXX
XX111
ή
X111X why not have 33,33% in both columns
1XXX1
ή
X1X1X why not have 33,33% in both columns
1X1X1
ή
X1111 why not have 33,33% in both columns
1XXXX
etc etc etc etc
Two columns cannot be 33,33% by weight and the rest are for rubble ...
 
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When have two columns? 33,33% probability why not have the other couples?
XXX (where X = UNDER)
11111 (where 1 = OVER) 5 under + over probability 33,33%
then with your own reason why we don't have 33,33% in both columns
11XXX
XX111
ή
X111X why not have 33,33% in both columns
1XXX1
ή
X1X1X why not have 33,33% in both columns
1X1X1
ή
X1111 why not have 33,33% in both columns
1XXXX
etc etc etc etc
Two columns cannot be 33,33% by weight and the rest are for rubble ...



.
I didn't understand what you are answering me, but ok, thanks.

Sent from my SM-G928F using Tapatalk
I didn't understand what you are answering me, but ok, thanks.

Sent from my SM-G928F using Tapatalk
[/ QUOTE



Dude gdouvl 1984
Thank you very much for your consideration and we will try to implement it soon. We reiterate that
1.We play on the internet where much shorter development is needed
2.We give value to 1 match or 2 which can be football or anything else and
3.If we make a prediction, we find that it is not going well and we use cash out.
 
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