Develop a new construction program

[Balaton]

If it is so

1
1
1
1
1
1x
1x
1x
1x
1x
1x
1x

asking for 8 ..... 1x .... from 8-to-8 0 to 0

But I want to have in all the columns both points and the only case for me to lose is for me to have 8 consecutive Xs. .

 

[Balaton]

101 1X
102 1X
103 1X
104 1X
105 1X
106 1X ΔΕ
107 1X ΔΕ
108 1X ΔΕ
109 1X ΔΕ
110 1X ΔΕ
111 1X ΔΕ
112 1X ΔΕ
As I see the system the code 105 in no case plays the point X because with the double chances there will be 8 X, so the code 105 plays a pure ace.
What I do not understand, why to have 5 matches in doubles is obviously in full swing and they do not play a double chance.
The right way to develop is to give the 12 matches in doubles (without double chance)
and from code 101 to 108 to give 8 X and ask for 8-8 X from code 102 to 109 again 8 X etc and they will be created
5 basic columns with 8 X enter a group of 5 basic and we ask them to go 0-0 (ie none of the 5 basic to have 8 X in a row). By shrinking the cards, the doubles that will appear will play a double chance .....

Nice..

 

[stxma]

 

[Balaton]

What I do not understand, why to have 5 matches in doubles is obviously in full swing and they do not play a double chance.

Because someone who does not know Andromeda well can not do it by hand, I tried, it is tedious, I gave it up and calmed down. Now that you have told me how I will do it.

 

[nmpropo]

Because someone who does not know Andromeda well can not do it by hand, I tried, it is tedious, I gave it up and calmed down. Now that you have told me how I will do it.

I hope it works

 

[nmpropo]

I hope it works

I do not know andromeda but it does not have basic columns? Give 8 X to the first basic and a total of 5 basic
with limits in each basic 8-8 and in one team the basic limits 0-0 (none passes)
So where is the bulletin I see coming in the next column of consecutive?

 

[Balaton]

I do not know andromeda but it does not have basic columns? Give 8 X to the first basic and a total of 5 basic
with limits in each basic 8-8 and in one team the basic limits 0-0 (none passes)
So where is the bulletin I see coming in the next column of consecutive?

Andromeda does it, for example, it turned out to me that in a dozen to have from 0-0 8 consecutive X is 14 columns. Somewhere there I was expecting it to be but I did not know exactly how many and I could not do the development by hand. Once I tried to do it I got dizzy and gave up.
You do not see it, you have to sit down and calculate it

 

[Balaton]

I do not know andromeda but it does not have basic columns? Give 8 X to the first basic and a total of 5 basic
with limits in each basic 8-8 and in one team the basic limits 0-0 (none passes)
So where is the bulletin I see coming in the next column of consecutive?

So I put the following systems that he could and did run:
14 games double points not 10 consecutive X
14 games double points not 9 consecutive X
14 games double points not 8 consecutive X

Then I went to put it
14 games double points not 7 consecutive X
and there in the collection of columns he issues 1 card with 14 doubles. Logical for the program, this is how it should work. So it can do up to there and beyond the rest by hand if we assume that someone will want it which will come out I believe in the approximately 28 columns somewhere there.

 

[nmpropo]

So I put the following systems that he could and did run:
14 games double points not 10 consecutive X
14 games double points not 9 consecutive X
14 games double points not 8 consecutive X

Then I went to put it
14 games double points not 7 consecutive X
and there in the collection of columns he issues 1 card with 14 doubles. Logical for the program, this is how it should work. So it can do up to there and beyond the rest by hand if we assume that someone will want it which will come out I believe in the approximately 28 columns somewhere there.

It does not make sense to have only one ticket, unless the program does not give you all the features you need
to buy it.
You do not write how many tickets he gives you in each case

 

[Balaton]

It does not make sense to have only one ticket, unless the program does not give you all the features you need
to buy it.
You do not write how many tickets he gives you in each case

The program can not combine 1-X and 1X (DE). We now consider in the summary that what the bulletin presents in double is a double opportunity. When you go to do this at 14 with no more than 7X, a card with the 14 doubles throws you in the contraction. For better or worse it does. Now I try to do it in an unorthodox way, that is, to put 7a on it and to set a condition of no more than 4X and to put the columns AX B and to throw out the double columns! Fortunately, it is still August and I manage to calculate them, I will do it little by little, I will have taken them out in 20 days for 10 matches or more!

 

[stxma]

Then I went to put it
14 games double points not 7 consecutive X
and there in the collection of columns he issues 1 card with 14 doubles. Logical for the program, this is how it should work. So it can do up to there and beyond the rest by hand if we assume that someone will want it which will come out I believe in the approximately 28 columns somewhere there.

No, the program came out correctly, I said 14 doubles, because that's how you set the limits, when the limits are equal, you have to have extra counters, because it catches 2 heptades x (symmetrical), so from the 2 you ask for 1 to 1

 

[stxma]

View attachment 26460 View attachment 26460


If I remember correctly, it is, for example, the first match with the 14th, the 2nd match with the 13th, etc.
or the 1st race with the 8th the 2nd race with the 9th etc.
Now not accepting the 7 consecutive Xs is strange.
..

I mean 2 symmetric 7s
---------------------
1
2
3
4
5
6
7
---------------
8
9
10
11
12
13
14
------------------
Of these two just keep one, but play each time an a
on both. Also since we have 14 x, it can easily say symmetrically from ******** 0-1-2-3-4-5-6 ******* so you will keep a 7αδα
Accepts 7 consecutive as long as we ask for them
right, the problem is not that it does not accept, since it produces 14 x it has 2 seven consecutive

 

[Balaton]

Guys, he did it, he took out 28 columns that I was counting. So, in essence, from some point and then you go against them, you ask for 0-0, you make a contraction and your tickets come out.

 

[stxma]

Guys, he did it, he took out 28 columns that I was counting. So, in essence, from some point and then you go against them, you ask for 0-0, you make a contraction and your tickets come out.

You would like it a bit like that ..!

 

[Balaton]

You would like it a bit like that ..!View attachment 26465


View attachment 26467

To tell you the truth yes ...

 

[stxma]

But here we need .... special contraction ...... maybe Larry has some idea for a few tickets.

 

[nmpropo]

When he gives you 15 tickets in 28 matches, I do not think that the tickets will be shortened. .....

 

[stxma]

When he gives you 15 tickets in 28 matches, I do not think that the tickets will be shortened. .....

With the D.E. the problem is because it shrinks the standards while connecting the ace and the D.E. as a double does not. Or I do not know how to do it. For example it could be doubled ....... 1 - (1x d.e)

 

[stxma]

In Balaton's place I would make the 23 columns and the 14 D.E. a column with a rate as best as its 23

 

[Larry]

The solution (and I wrote it before) was given by him @nmpropo, some answers earlier.

You give 12 duplicates, you give terms and you collapse in the end. The bad thing is, however: The volume you are playing with all the cards is fixed, and if it hits you, it may hit you with all the double opportunities and not the 5 column. get crumbs.

Now for the collapse you are saying, set a clear example to understand and see if I have any idea.