Develop a new construction program

Balaton

Well-Known Member
1 Nov 2008
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Larry what I had written to you one day says. But what I didn't say then was which columns to put out and in what order. If we go into the process of talking about percentages and putting percentages at points then the columns should come out of a higher verification rate to the smaller one.

That is, if we have an 5 match of 70-20-10, 3 of 60-40-0 and two 40-40-20 the first column that should have been 70-70-70-70 -70-60-60 now whether the player sees this column first and plays it is another matter and it is his choice, but the program should extract the columns from the highest verification rate to the smallest and tell the player give me the first 60 columns. One could tell the percentages of the 40 to 40 columns to come out but this is not very useful. It is better if he knows what money he is playing to make the columns and if it is possible to put the amount to play and if he wants to have the option of Dutching so he knows and how much to bet on each column to get the same profit that and if done!

PS I have deliberately put in the last case ace and x to have the same percentages, in such a case the program may not be able to give you which column should be the first to get the point yields and the yields of points to remove the columns if two points in the same match have the same percentage!
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stxma

Well-Known Member
1 Oct 2008
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That is, if we have an 5 match of 70-20-10, 3 of 60-40-0 and two 40-40-20 the first column that should have been 70-70-70-70 -70-60-60
The subject of percentages, at least as you can see above, gets better with ..... first ...... second ..... third ... points.

Percentage can be set in other ways as well.

A) In the total entries for example hold me 100 columns whose distribution is 70-20-10

B) Percentage of position

Larry

Well-Known Member
1 Apr 2010
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Currently, as in the program, it displays the columns in ascending order, depending on the product of the column's output.
If we think that OPAP is good at making returns, then this is the chance-based series. I also already have the option to trim the performance-based columns, such as if the system is performing from 1000-5000, because usually 1000 does not come out, hunting somewhere in the middle, ie as if I want all the columns from 1500-2500.
If we think you better predict, you should give it as the first-second-third that the verse says.
In dutching now, suppose I have 50 20 - 400 rendering columns and want to do dutching, what does OPAP mean since the subdivisions are 25 min?
Personally, I build the system, put the columns in ascending order, and if I see low-yield columns, I do * 2 or * 3 and finally.
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stxma

Well-Known Member
1 Oct 2008
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In our case right now, one way is to derive the percentages ... but who can do it?

nmpropo

Active Member
15 Nov 2011
24
93
33
Mr. George, are you having fun with us?

Why restore it? Write to see it after you've got it.
We have and say 10 triple columns 81 bulletins 8 Stage play By the same tokens the columns are only
12258 will count as much in your program and any pre-program type.
We ask for 4 matches 3-4 points (aces) 6 triple matches we ask for nothing.
System performance with 3 aces 100% 7 fours with 4 aces 100% only 25 fours !!
1 bulletin
1 standard
1 standard
1 standard
1X
1X
1X
1X
1X
1X
1X 14 columns from duplicates we ask for a point
2 bulletin
1 standard
1 standard
1 standard
2
2
2
2
2
2
2 7 columns We request a point from the 2 points
3 bulletin
1 standard
1 standard
X2
1 standard
1X
1X
1X
1X
1X
1X 14 columns We ask for a duplicate point
4 bulletin
1 standard
X2
1 standard
1 standard
1X
1X
1X
1X
1X
1X 14 columns We ask for a duplicate point
5 bulletin
X2
1 standard
1 standard
1 standard
1X
1X
1X
1X
1X
1X 14 columns We ask for a duplicate point
6 bulletin
1 standard
1 standard
vacuum
1 standard
2
2
2
2
2
2 Columns 6 We are requesting a point from the 2 points
7 bulletin
1 standard
vacuum
1 standard
1 standard
2
2
2
2
2
2 6 Columns We request a point from the 2 points
8 bulletin
vacuum
1 standard
1 standard
1 standard
2
2
2
2
2
2 6 columns We request a point from the 2 points

void = no point playing. The duplicates are in full development.
don't say it's a tough weekend term on 14 double passed 5 on 5 points
and grabbed 12 by the 14 dual.
True or false that I only play with 0,66% of columns, true or false that I have at 3 points
100% 7 fours and at 4 points 100% 25 fours.
play terms and conditions horizontally perpendicular vertically discontinuous and and and and and and only play with 0,66% with whatever terms you want to play 10 triple with 81 columns?
Offered by syn1 2-9-2019 George Triantafyllou

and with these points all triples play 1 = 2 odds X = 2 odds 2 = 2 odds
is 2X2X2X2 = 16X7 quadrants = 112 rendering and playing only 81 columns
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Larry

Well-Known Member
1 Apr 2010
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Sun George you don't play a good ball.

1. You display thousands of columns at the beginning and magically make them 81. How; Just converting duplicates into duplicate opportunities. Basically you don't have 10 triple, 10 double, 1 single point and 1 DE
2. If I only play 4 triples requesting 3-4 aces in a set of 2.00-3.00-3.00 odds, I have 5 columns:

1111 performance 16
111 [Χ2] rendering 12 = 2 * 2 * 2 * 1,50
11 [Χ2] 1
1 [Χ2] 11
[X2] 111

I don't equate, in the first column I get 16 / 5 = 3,2 times the capital and in the other I get 12 / 5 = 2,4 times.

But because I do not have it by prediction, I only play acceptable. If I get 3 / 4 every time, I have 3 * 2 / 4 = 1,5 times the capital and because I don't forecast correctly, I get 2 / 4 and I'm on my money.

Mathematics gets into the system and you know why? Because you got to play 10s and got in or lost the advantage (if you had one) and lost your profits.
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stxma

Well-Known Member
1 Oct 2008
1,073
304
83
Sun George you don't play a good ball.

1. You display thousands of columns at the beginning and magically make them 81. How; Just converting duplicates into duplicate opportunities. Basically you don't have 10 triple, 10 double, 1 single point and 1 DE
2. If I only play 4 triples requesting 3-4 aces in a set of 2.00-3.00-3.00 odds, I have 5 columns:

1111 performance 16
111 [Χ2] rendering 12 = 2 * 2 * 2 * 1,50
11 [Χ2] 1
1 [Χ2] 11
[X2] 111

I don't equate, in the first column I get 16 / 5 = 3,2 times the capital and in the other I get 12 / 5 = 2,4 times.

But because I do not have it by prediction, I only play acceptable. If I get 3 / 4 every time, I have 3 * 2 / 4 = 1,5 times the capital and because I don't forecast correctly, I get 2 / 4 and I'm on my money.

Mathematics gets into the system and you know why? Because you got to play 10s and got in or lost the advantage (if you had one) and lost your profits.
Here I will disagree somewhat, as it is a matter of standards simply covering the 4 double top of the four with duals.

nmpropo

Active Member
15 Nov 2011
24
93
33
Sun George you don't play a good ball.

1. You display thousands of columns at the beginning and magically make them 81. How; Just converting duplicates into duplicate opportunities. Basically you don't have 10 triple, 10 double, 1 single point and 1 DE
2. If I only play 4 triples requesting 3-4 aces in a set of 2.00-3.00-3.00 odds, I have 5 columns:

1111 performance 16
111 [Χ2] rendering 12 = 2 * 2 * 2 * 1,50
11 [Χ2] 1
1 [Χ2] 11
[X2] 111

I don't equate, in the first column I get 16 / 5 = 3,2 times the capital and in the other I get 12 / 5 = 2,4 times.

But because I do not have it by prediction, I only play acceptable. If I get 3 / 4 every time, I have 3 * 2 / 4 = 1,5 times the capital and because I don't forecast correctly, I get 2 / 4 and I'm on my money.

Mathematics gets into the system and you know why? Because you got to play 10s and got in or lost the advantage (if you had one) and lost your profits.
In the name of the god you saw the double opportunities in the first card they play three standards
and 7 duplicates ie 2 + 2 + 2 + 2 + 2 + 2 + 2 = 14 columns after I ask for a point to be passed (1X)
the same sheet is repeated with the three standard and 7 duplicates and I ask for a column of 7 columns
After all, I have written the columns in each bulletin play the double full


and to make you know which retailer we are playing 5 triple in the first 2 matches we ask for 1-2 aces column count
type 86 columns.
Playing columns 23 4 bulletins. One 4 ace holder with 2 holder 7 aces holder
playback analysis
1standard
1X
1X
1X
1X
We ask the duplicates to catch a single (not double opportunity) 8 columns

1 standard
2
2
2
2 We request a point from the 4 double columns

X2
1 standard
1X
1X
1X
We are requesting a point from the 8 duplicate columns

- empty the first race
1standard
2
2
2 We request a double 3 column

Still doubt what the show is doing?
The system is nowhere to be bothered but way (thinking)
losing 2 to 4 games (like I once lost) is the wrong way to play, but who am I to suggest how to play
Note: And I don't need a program to play play systems
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Larry

Well-Known Member
1 Apr 2010
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I can't understand you.

Above you write 3-4 aces on 4 triples and also 6 triples unconditionally and request quadrants.
What you write doesn't make sense, it's sinister. If anyone understands, let's make it simple.

stxma

Well-Known Member
1 Oct 2008
1,073
304
83
I can't understand you.

Above you write 3-4 aces on 4 triples and also 6 triples unconditionally and request quadrants.
What you write doesn't make sense, it's sinister. If anyone understands, let's make it simple.
Let me just break it down From the 1-2-3-4 race that is a nonsense just asking for 3 from 4 ..... = 4 triples

1-2-3...........=1-1-1
1-2-4...........=1-1-1
1-3-4...........=1-1-1
2-3-4...........=1-1-1

and in 7 always keep a note of 21 whenever 21 * 4 = 83

in essence it says 3 equals but with 2 points it becomes 4, because of the gap and x2
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Larry

Well-Known Member
1 Apr 2010
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853
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Let me just break it down From the 1-2-3-4 race that is a nonsense just asking for 3 from 4 ..... = 4 triples

1-2-3...........=1-1-1
1-2-4...........=1-1-1
1-3-4...........=1-1-1
2-3-4...........=1-1-1

and in 7 always keep a note of 21 whenever 21 * 4 = 83
Thank you for stxma's reply.

Bypass that is not 81 columns that writes above.

And is this system not mathematical? Will you all drive me crazy?
Do you play triple unconditional on op.ap and consider it a diamond system?
I have also proven that you are in the buns. Now if you want to say I got 25 quadruplets and got + 30% in the capital, okay, what can I say. I only play 4 triples and get 3 times on average.

stxma

Well-Known Member
1 Oct 2008
1,073
304
83
Thank you for stxma's reply.

Bypass that is not 81 columns that writes above.

And is this system not mathematical? Will you all drive me crazy?
Do you play triple unconditional on op.ap and consider it a diamond system?
I have also proven that you are in the buns. Now if you want to say I got 25 quadruplets and got + 30% in the capital, okay, what can I say. I only play 4 triples and get 3 times on average.
I do not see very well when adding some 21 * 4 = 84 typefaces

stxma

Well-Known Member
1 Oct 2008
1,073
304
83
If it catches 25 it goes 600 € + with 1 € column. Whenever you give roughly 100 € how much does it earn% because I don't know how to do it.

nmpropo

Active Member
15 Nov 2011
24
93
33
I can't understand you.

Above you write 3-4 aces on 4 triples and also 6 triples unconditionally and request quadrants.
What you write doesn't make sense, it's sinister. If anyone understands, let's make it simple.
If you don't make sense with the 5 triple instance I can do nothing more, anyway an 5 triple attempt
call for 1 to 2 aces in 2 first matches We ask for columns are 23 instead of 86
3 triples are unconditional.
1 analysis bulletin
1standard
1X2
1X2
1X2
1X2
Here we call the 4 triple 1 point from the 1 triple 3 columns
1 point from the second triple columns 3
1 point from the third triple columns
and 1 point from the fourth triple (whichever point comes from
triple catch) and the columns are 12 if the oppa leaves us
playing triple this look would have been our ticket.
In the first card because the second game triple triple play
the term 1-1 is also playing (we ask for 1-2 aces in the first two matches)
the second bulletin
X2 the first race
1 the second race as standard
1X2
1X2
1X2
This format would have the second card if they let us play triple op.
and 3 triple the columns are 9 (3 + 3 + 3) and its two columns double
second race. I do not describe any more
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Larry

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1 Apr 2010
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If it catches 25 it goes 600 € + with 1 € column. Whenever you give roughly 100 € how much does it earn% because I don't know how to do it.
How will it go for 600? Suppose he got 4 on 4 on the first 4 triples, so he has 4 triples. Because these 4 triplets each have definitely 7 points, they end up having 28 triplets. Correctly;
If each quadrant has 2 * 2 * 2 * 2,5 = 20, then it has 28 * 20 = 560 euros, with 1 euros per column.
So with 84 euros it got 560.
If I play it differently and play 4 3-4 match system, I give 16 euros per column, 80 total.
I get 8 * 16 = 128 * 4 = 512 for the 3 groups and
16 * 16 = 256 for 4, so 512 + 256 = 768 set.

Conclusion: 768-560 = 208 in the tiger's paw.
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Larry

Well-Known Member
1 Apr 2010
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I'm not describing anything else
Well, you can't write simple things?

I have 10 triples, I play 10s.

On the first 5 triples I ask for 2-4 aces, 30 columns.
On the other 5 I request 4-5 aces, 6 columns.

Total 180 columns.

If you can't write, what can I say.

stxma

Well-Known Member
1 Oct 2008
1,073
304
83
How will it go for 600? Suppose he got 4 on 4 on the first 4 triples, so he has 4 triples. Because these 4 triplets each have definitely 7 points, they end up having 28 triplets. Correctly;
If each quadrant has 2 * 2 * 2 * 2,5 = 20, then it has 28 * 20 = 560 euros, with 1 euros per column.
So with 84 euros it got 560.
If I play it differently and play 4 3-4 match system, I give 16 euros per column, 80 total.
I get 8 * 16 = 128 * 4 = 512 for the 3 groups and
16 * 16 = 256 for 4, so 512 + 256 = 768 set.

Conclusion: 768-560 = 208 in the tiger's paw.
How would you praise the 5 triples for twins? against 23 columns;

Larry

Well-Known Member
1 Apr 2010
1,324
853
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stxma, if the system cannot be parsed I can't answer, this is my last answer.

In any case, if you play anything unconditionally you are lost due to a rake.

Mathematical office.

nmpropo

Active Member
15 Nov 2011
24
93
33
let's not get out of our subject

waiting for people and people :)
and my last answer each race was averaging 2,60 both were Larry 2.6 X2.6 X 2.60 X 2.60 how much he did = 45 and something went 4 to 4 (from the requested 3-4) and 12 to 14.
And the 14 games performance was from 2,50 to 2,75 find games
with these performances and passing 12 to 14 and saying it again.
Good continuity to all of you
2-9-2019 George Triantafyllou
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