Develop a new construction program

stxma

Well-Known Member
1 Oct 2008
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And yes you can play 7 standard and 7 double (leave triple) on 2
newsletters and the agent to print on a newsletter as long as the agent is your best friend (just not involved) because of the risk
and it's not misinformation that I gave the agent with a 6 duplicate written as it used to be, I just didn't realize that the duplicate I gave her was normally manually passed giving the duplicate normal 1X
Truth or lies so you can play 7 standard and 7 double in
2 bulletins and the agent to print your standard and duplicate bulletins tomorrow's solution if the agents say you are not lying,
because my agent showed me how to do it. The solution tomorrow ....
5-11-2019 George Triantafyllou
The issue again is the expansion (in a card) of a card so what can I play, especially if it is for 15? Also how do you play 14 in 2 cards?

1
1
1
1
1
1
1
12
12
12
12
12
12
12
 
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nmpropo

Well-Known Member
15 Nov 2011
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The issue again is the expansion (in a card) of a card so what can I play, especially if it is for 15? Also how do you play 14 in 2 cards?

1
1
1
1
1
1
1
12
12
12
12
12
12
12
Let me give you the solution as the agent told me.
On one sheet you give the standard and on the other
you give the duplicates with the separate dots, that is the 7 duplicates
any code twice 14 set and with the two sheets as if the agent passed them as 7 standard and 7 double, they have the option
from software to a bulletin with 7 standard and 7 duplicate
and will print a sheet with 7 standard and 14 double matches.
The agent also has the option of giving him some duplicates
on plain paper to manually pass them eg 7 does not want double
to pass 14 points simply gives the 7 duplicates 12-12-12-12-12-12-12 and the machine gives each code twice and has 14 points on the printout.
If the agent wishes to because 50 people are supposed to play in duplicates, the agent must manually pass 50 cards.
Agents have also complained about this miserable software
that have made their lives difficult for the players .....
Note: When manually switching to duplicates eg 7 you can request 2kates 3kets etc.
 
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stxma

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1 Oct 2008
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However, from what I have understood, in full the whole bulletin (single-double-triple in total) has to slash 15, eg (4 triples = 12 positions) a double = 2 positions (and a single = one position) Whenever in collapse it will allow for example up to 7 duplicates and single.
 
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nmpropo

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15 Nov 2011
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However, from what I have understood, in full the whole bulletin (single-double-triple in total) has to slash 15, eg (4 triples = 12 positions) a double = 2 positions (and a single = one position) Whenever in collapse it will allow for example up to 7 duplicates and single.

If you do not have the agent stuck, we play in an 1 standard and 7 duplicate.
Responsible for this miserable software are Intralot's lads,
trying to make life difficult for agents and players.
But always some will overcome this obstacle.
Example 6 Triple Unconditional for 2kill 45 Columns in 15 Bulletins
and nowhere is double.
System performance is 100% 3 to 15 doubles accordingly
by displaying 1 or X or 2 points
6-11-2019 George Triantafyllou
 
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stxma

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Example 6 Triple Unconditional for 2kill 45 Columns in 15 Bulletins
and nowhere is double.

6-11-2019 George Triantafyllou
Andromeda is collapsing 3 bulletins, I hope it's right!
 
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nmpropo

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Andromeda is collapsing 3 bulletins, I hope it's right!
1. how many columns are in 2 values ​​without any condition? (if it's 45 columns you're on the right track)
2. guarantee of up to two pairs
3. Collapse does with double? if so how will the double with the new data of the coupon pass.
4. Are duplicates unconditional?
5. The growth I've had is nowhere to be seen
 
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stxma

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1. how many columns are in 2 values ​​without any condition? (if it's 45 columns you're on the right track)
2. guarantee of up to two pairs
3. Collapse does with double? if so how will the double with the new data of the coupon pass.
4. Are duplicates unconditional?
5. The growth I've had is nowhere to be seen


I hope we are talking about the same system if I calculate correctly based on your thinking.

1
χ
2
1
χ
2

the n column

1
1
2
2
χ
χ

and 15 doubles the column

1
1
1
1
1
1
 

nmpropo

Well-Known Member
15 Nov 2011
386
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I hope we are talking about the same system if I calculate correctly based on your thinking.

1
χ
2
1
χ
2

the n column

1
1
2
2
χ
χ

and 15 doubles the column

1
1
1
1
1
1
1. You didn't reply if the columns are 45
2. Other columns give 15 doubles, not just 6 aces
3. Again I stress that growth has not happened anywhere
 
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Larry

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1 Apr 2010
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In any case, it is not possible to tell the agent "play the ticket" every time. Especially peak hours ...
 

Larry

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1 Apr 2010
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Good evening and Happy New Year,

After some time an update, some things have been fixed (columns collapse etc). A test version for a three day link

Link deleted.

Good profits to everyone.
 
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Larry

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1 Apr 2010
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4 triple 2-4 straight columns 33 17 bulletins are normally only 11
All systems have this behavior .....

Yes, it really is.

With the new collapse coming out so much, it wants a bit of work for the triples yet. In double collapse it comes out. You can try it in the test file I uploaded.

Also to mention that I have developed a tool for minimum shorter variable length, based on columns. Example:

If I play 8 doubles and ask for the first 4 doubles 2-4 aces and similarly for the other 4 doubles, there is a total of 121 columns. If I want to have at least one bar, how many columns are needed?
The program says 35 columns.
Another example:
6 unconditional triples, columns 729 and I want to have 100% a triple: columns 3.

If anyone can, let's show a few variables to test.
 
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stxma

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6 triples 100% 3x 6 columns.

1..2..3..4..5..6

1..1..x..x..2..2
1..x..1..x..x..2
1..x..1..x..x..2
1..x..1..x..x..2
1..x..1..x..x..2
1..x..1..x..x..2

Also 8 duplicates without condition for 100% 6ar = 12 columns.
 
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Larry

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1 Apr 2010
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6 triples 100% 3x 6 columns.

1..2..3..4..5..6

1..1..x..x..2..2
1..x..1..x..x..2
1..x..1..x..x..2
1..x..1..x..x..2
1..x..1..x..x..2
1..x..1..x..x..2

Also 8 duplicates without condition for 100% 6ar = 12 columns.

You didn't understand me stxma.

I don't mean playing 6 or 8.

I mean playing the shortest length that covers the columns.

If I understood well, that's what nmpropo was saying above, that is, I play in full 8s, but I cover 6s.
 
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stxma

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You mention the variables and the variables are not clear! If I understand correctly, you mean, e.g.

6 triples

Development - 3d system

where to have at least 100% a 3?
 
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Larry

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You mention the variables and the variables are not clear! If I understand correctly, you mean, e.g.

6 triples

Development - 3d system

where to have at least 100% a 3?

Yes exactly.

For example, I play 8 doubles, I ask 2-4 points in the first 4 doubles and the same in the other 4.
In 8 steps, it outputs 121 columns. If I play 6pads, covering 121 columns, it turns out 35 columns. So if I fall into my predictions, I'll get at least one 6. The good thing with these systems is that even if you lose a double, even if you've played 1X and come out 2, you hope you can get 6s.
Slow chances of course, but you have some and you also play about 4 times less columns.
 
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Larry

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1 Apr 2010
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Without the terms amounts of columns (6pcs) do you take it out?

I don't know if I'm getting close to the optimum, it comes out of 256 to 69 columns.

In fact the optimal is 64 columns and I explain:

If you play 6 games full, it's 64 columns, so whatever the other 2 come in, you've got 6.

The algorithm works otherwise, however, and only makes sense for columns in terms.
 
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stxma

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I don't know if I'm getting close to the optimum, it comes out of 256 to 69 columns.

In fact the optimal is 64 columns and I explain:
Because I analyze it by hand and find it difficult to adjust it to 8 in 9 doubles for 6 weeks
and take it out = 64 columns (6pads), without conditions.
 
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