**A: SAMUEL RIG TERMS - FIX 13**
The points here in the table are the same, but they change every week, so this term is reported as weekly and not permanent. For example, I will be able to put the digits in different parts of the table, and I will not be able to see how much is passing.

You can not even see how much this term takes in the total number of winners, since every week you will change the positions of the points!

Note that such terms produce a negative rake, because they last longer than they cut.

================================================== ====

Sorry, day Champions League, I copy question and answer

for the way table 1-42 comes out

================================================== ====

QUESTION:

I mean even the first match 12-20-40 .... total here 70

the matches you showed have a different set,

Based on what do you start with?

The classic sum has for example a total of 10 or 100

but in all races.

Still what program is for prep?

if you want give me information about the program.

==================================================

ANSWER

The process is long, but after years it is automated.

The M.O.% of percentages for each match comes out.

Then I see what is the largest percentage% and I call it 1.

After the 2nd and I call it 2 etc, this is how a sequence of numbers from 1 to 42 is made.

In other words, the 42 points of the 14 triples (3 out of 14 = 42) are classified in a decreasing evaluation.

Because I delete them from (on the page), I will give you an example from the Infobeto photo.

The best point (No. 1 in the table) on Saturday was the ace in game 12 (of City).

That is, this from the M.O. of percentages had the highest%.

You do not see it, but I tell you it was 79,8%.

I am writing to you about the match 12 ->

the 3 -> 79,83 (1) --- 13,925 (X) --- 6,244 (2).

The next (2) was the ace of Chelsea (13 games), etc.

This percentage was 73,4%

Again -> match 13 -> 73,417 (1) --- 17,654 (X) --- 8,929 (2).

Because these small numbers represent the best points,

the smaller the sum, the easier the card is.

The minimum is 105 and the maximum is 440.

But how to find many winners, when they have to collect 4.782.969 columns?

So we also chase a low sum (easy card) after we succeed

with this table to keep relatively few columns in the 14 triples.

If we ask for a sum of 105-195 in this example, then the final columns are 45.924, but in verification we go down to 30 times out of 80 in total.

while at 105-210 the finals are 106.852.

We can play

the 10 -> 1X

the 11 -> 1X

the 12 -> 1

the 13 -> 1

the columns from 106.852 become 54.781.

Then you put basic, symmetrical etc etc and go down as much as you want.

This recording (80 times) is the freshest package I have,

I used to have a slightly different source, so I had different table results,

with a more open sum.

Any program that plays a summation table without committing itself horizontally to a sum of 100,

makes you use it.

Then you have to print coupons, unless you know the tricks

made by sending tickets from H.Y. directly to an OPAP machine

with the appropriate cable, without printing from a printer.

That's all !!!