FAMILY SAMI - FIX 13 TERMS

Kentribet

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4 Feb 2012
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A: SAMUEL RIG TERMS - FIX 13

It has nothing to do with the program.

You want to say that in the example of the 3 triples I gave
and give Sum 6-17
and when the sum of 7 comes I will have a trinity ???
NATURAL!
So you can apply it to betting.
And if you are thinking of playing a nail sum (the 15 we said) that produces 7 columns and is the "heart" of the columns, then ask for 2 to 3 in each and with great odds you win.
These have always been done.
And many more in doubles !!!
 
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stxma

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A: SAMUEL RIG TERMS - FIX 13

NATURAL!
So you can apply it to betting.
And if you are thinking of playing a nail sum (the 15 we said) that produces 7 columns and is the "heart" of the columns, then ask for 2 to 3 in each and with great odds you win.

If I understand correctly I say I keep the 15 sum
and 7 columns and in a system of 2-3 each trinity
a total of 28 columns.

So if the 15 sum sits down I will win 1 triple and 3 doubles !!
 

Kentribet

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A: SAMUEL RIG TERMS - FIX 13

If I understand correctly I say I keep the 15 sum
and 7 columns and in a system of 2-3 each trinity
a total of 28 columns.

So if the 15 sum sits down I will win 1 triple and 3 doubles !!

YES.
I am developing you (HORIZONTAL)
the above 7 columns that have a sum of 15
to measure

1X2
12X
X12
XXX
X21
21X
2X1

do whatever dialogues you want!

But let me tell you that if it comes
1XX
so you do not have 3 correct points,
you will have 3 pairs.
K.
 
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snoopjohn

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22 Jan 2012
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A: SAMUEL RIG TERMS - FIX 13

Dude snoopjohn how can we return to PROPO with such data that exists today with 14 games and 0,25 minutes per column. Indeed, the study is currently only on 14 triples, because only then do you sleep peacefully without caring who will win. But how will the columns go down to the desired limits. I think it is difficult. whatever conditions you put in the end you will not be able to avoid conflicts. Indeed symmetrical pairs are good in a team and cut, the problem is that conditions that pass on the winners 100% you can not find many. If you find terms that pass 90 and 95%, if they are more than 15, in total the 14 arias will be minimal or zero. I have spent countless hours studying Propos because it was something I really liked. I have come to the conclusion that the only solution to see 14 arias is to study 3-4 players and to play the common columns on Sunday. If they all stop at 5000 columns, the total will not be more than 700.
user_offline.gif

Brother, as things stand today, there is only one way you can chase the prop, in my opinion, and always with 14 triples.
With a cartridge in serum (s) where in total he spends more, than he cuts, and with statistics in the last 10-20 winners. For example, if you have a condition that takes even 10% of the total number of winners and cuts more than 90% of the total, then first of all you have a positive rake on your side. And secondly, if you see that in the last 15-20 winners the term has not been verified, then statistically it will come out in the next close draws. You can also check how much delay a serum has made on all the winners.
in this way in the long run you will be 100% won, because you will have the positive double rake on your side.
The only downside is that we need a lot of capital and of course a team aiming for a football season.
If you can play with one or 2 standards even better, but do not forget that the term can be passed and you can lose your standard.
On the plus side, it eliminates unhealthy sugary foods from one's diet.: fish:

As for the way you suggest, in my opinion it is completely wrong with the common columns, because all 4 players must get 14 points, in order to be in on Sunday.
It would be better to play the separate columns, so that even if one has a 14 to fall into.
The package that I gave at the beginning was passed by all the winners, but that does not mean that it will pass the next Sunday.
I just put up columns where it meets all the conditions from the previous winners.
In the 8th Competition 19/02/2012 -20/02/2012 on Sunday he gave the 14th, with winnings 3.260,79 euro (the column was easy)
in the 9th Competition 26/02/2012 -27/02/2012
τon Sunday gave again the 14th, with profits 2.224,97 euro (the column was easy again).
2 consecutive 14 arias with 5.06% of the complete regardless of forecasts, with a total of 241.804 columns, but your complete one slaughters it .....
 
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snoopjohn

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22 Jan 2012
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A: SAMUEL RIG TERMS - FIX 13

Good evening.

The best and fastest way to initially reduce columns is with a cumulative table.

The points of the 14 triples from 1 to 42 (14 out of 3) are evaluated
where smaller numbers are best. The range of the table is from 105 to 440 and we ask from 105-220. The final columns with the table alone are 176.403 and all points play normally.

Whoever wants then puts his own terms and some standard or double to reduce it.

A "very old"

Costas.

The points here in the table are the same, but they change every week, so this term is reported as weekly and not permanent. For example, I will be able to put the digits in different parts of the table, and I will not be able to see how much is passing.
You can not even see how much this term takes in the total number of winners, since every week you will change the positions of the points!
Note that such terms produce a negative rake, because they last longer than they cut.
 

Kentribet

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A: SAMUEL RIG TERMS - FIX 13

The points here in the table are the same, but they change every week, so this term is reported as weekly and not permanent. For example, I will be able to put the digits in different parts of the table, and I will not be able to see how much is passing.
You can not even see how much this term takes in the total number of winners, since every week you will change the positions of the points!
Note that such terms produce a negative rake, because they last longer than they cut.
================================================== ====
Sorry, day Champions League, I copy question and answer
for the way table 1-42 comes out
================================================== ====

QUESTION:
I mean even the first match 12-20-40 .... total here 70
the matches you showed have a different set,
Based on what do you start with?
The classic sum has for example a total of 10 or 100
but in all races.

Still what program is for prep?
if you want give me information about the program.

==================================================
ANSWER
The process is long, but after years it is automated.

The M.O.% of percentages for each match comes out.

Then I see what is the largest percentage% and I call it 1.
After the 2nd and I call it 2 etc, this is how a sequence of numbers from 1 to 42 is made.
In other words, the 42 points of the 14 triples (3 out of 14 = 42) are classified in a decreasing evaluation.

Because I delete them from (on the page), I will give you an example from the Infobeto photo.

The best point (No. 1 in the table) on Saturday was the ace in game 12 (of City).
That is, this from the M.O. of percentages had the highest%.
You do not see it, but I tell you it was 79,8%.
I am writing to you about the match 12 ->
the 3 -> 79,83 (1) --- 13,925 (X) --- 6,244 (2).

The next (2) was the ace of Chelsea (13 games), etc.
This percentage was 73,4%
Again -> match 13 -> 73,417 (1) --- 17,654 (X) --- 8,929 (2).



Because these small numbers represent the best points,
the smaller the sum, the easier the card is.
The minimum is 105 and the maximum is 440.

But how to find many winners, when they have to collect 4.782.969 columns?

So we also chase a low sum (easy card) after we succeed
with this table to keep relatively few columns in the 14 triples.

If we ask for a sum of 105-195 in this example, then the final columns are 45.924, but in verification we go down to 30 times out of 80 in total.
while at 105-210 the finals are 106.852.
We can play
the 10 -> 1X
the 11 -> 1X
the 12 -> 1
the 13 -> 1

the columns from 106.852 become 54.781.

Then you put basic, symmetrical etc etc and go down as much as you want.

This recording (80 times) is the freshest package I have,
I used to have a slightly different source, so I had different table results,
with a more open sum.

Any program that plays a summation table without committing itself horizontally to a sum of 100,
makes you use it.
Then you have to print coupons, unless you know the tricks
made by sending tickets from H.Y. directly to an OPAP machine
with the appropriate cable, without printing from a printer.

That's all !!!
 

Kentribet

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A: SAMUEL RIG TERMS - FIX 13

And I continue (to keep the question and the answer via email intact)

I believe that FIRST we play the forecasting terms and then we put the Statistics, (which we "tighten" as much as we want).
Other statistical terms apply when we expect a lot of aces (1) and others when the card appears to be more than double (2). More options and details another time.

I am not going to expand into controversies with the point of view of others, I have it as a "theorem".
K.
 

costsap

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9 and 2011
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A: SAMUEL RIG TERMS - FIX 13

OPAP is considering the possibility of returning PROPO to 13 a.m.
 

stxma

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1 Oct 2008
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A: SAMUEL RIG TERMS - FIX 13

Good evening.
The best and fastest way to initially reduce columns is with a cumulative table.
The points of the 14 triples from 1 to 42 (14 out of 3) are evaluated
where smaller numbers are best. The range of the table is from 105 to 440 and we ask from 105-220. The final columns with the table alone are 176.403 and all points play normally.

I do not know if I put it correctly but I hope you understand.

At least from your experience and after dealing with the term,
in the range 105-220 with (how many first points ...
1-2-3-4-5-6-7-8-9-10-11-12-13-14)=105 ειμαστε μεσα στον ορο?
Or from how much to how much?
Logically the .....to it will be ... 14.
The ...from....= ??
 
Last edited:

Kentribet

Member
4 Feb 2012
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A: SAMUEL RIG TERMS - FIX 13

I do not know if I put it correctly but I hope you understand.

At least from your experience and after dealing with the term,
in the range 105-220 with (how many first points ...
1-2-3-4-5-6-7-8-9-10-11-12-13-14)=105 ειμαστε μεσα στον ορο?
Or from how much to how much?
Logically the .....to it will be ... 14.
The ...from....= ??

Hi,

the first points, having results in the range 105-220 are from 6 to 12 (the 12 once).
The second points are in the range 2-6 and the third in the limit 1-3
In more detail:
the M.O. is
first ---> 8,55
second -> 3,95
third ----> 1,5

and all this in about 50 competitions (Wed-Sat-Sun)
where 15 had a jackpot.

See 1st column no.14 successes and 2nd column table sum.
These are the last 20 competitions.

0 283 0 274 0 360 0 248 0 220 0 239 1 235 1 190 0 248 10 171 0 228 0 207 11 166 0 323 0 298 1 187 0 228 0 227 0 185 8 178
They do not appear in columns, but continuously, in pairs.

That's all.
 

snoopjohn

New Member
22 Jan 2012
29
11
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A: SAMUEL RIG TERMS - FIX 13

[Quote
Logically the .....to it will be ... 14.
The ...from....= ?? [/ quote]

This makes it a perfect choice for people with diabetes and for those who want to lose weight or follow a balanced diet. from ξεκιναει απο το 1+2+3+4+5+6+7+8+9+10+11+12+13+14 = 105 provided they are shared in all of his matches. For example, you could divide 13 + 14 in 2 points in a match, then in this case you add 15 and set by 106. It is essentially the main pillar of the prop.

This makes it a perfect choice for people with diabetes and for those who want to lose weight or follow a balanced diet. to It's your right to define it, the bigger the number, the more money the pros will have.
If you can watch and put the points in the same way every week, then you will go in case of a carter with very good results.
eg in euro 145-152 has not appeared for `X` competitions, so you will start playing by tapping this range. You can set more widths, and ask to pass one table.
Example
120-130 in a table
155-165 to another
175 to 185 to another
and in total to ask for one to pass.
as you could set single or even sums, with 50% of the columns, so you will be in the 13 arias even with failure.
General tables are many good terms.
 
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stxma

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1 Oct 2008
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A: SAMUEL RIG TERMS - FIX 13

I probably do not understand something, or I do not formulate it correctly !!
Let me say it again

Let's say that from the column that brings out a sum of 105 (and I only live in this column)
(1-2-3-4-5-6-7-8-9-19-11-12-13-14)=105

From now on, this column after we ask for 105 sum..of course
that all 14 points will pass.

As long as the sum will grows up the column with sum 105
(1-2-3-4-5-6-7-8-9-19-11-12-13-14) θα αρχισει να χανει σημεια.
The question is up to the sum 220 how many points will be lost ??
The number of points from the column by sum 105 stay?

From editing I do I see that they are lost 5 points
η stay 9. (But I do not know if it is correct) for this I ask !!
 

snoopjohn

New Member
22 Jan 2012
29
11
3
A: SAMUEL RIG TERMS - FIX 13

I probably do not understand something, or I do not formulate it correctly !!
Let me say it again

Let's say that from the column that brings out a sum of 105 (and I only live in this column)
(1-2-3-4-5-6-7-8-9-19-11-12-13-14)=105

From now on, this column after we ask for 105 sum..of course
that all 14 points will pass.

As long as the sum will grows up the column with sum 105
(1-2-3-4-5-6-7-8-9-19-11-12-13-14) θα αρχισει να χανει σημεια.
The question is up to the sum 220 how many points will be lost ??
The number of points from the column by sum 105 stay?

From editing I do I see that they are lost 5 points
η stay 9. (But I do not know if it is correct) for this I ask !!

what processing do you do? and what do you mean the points are lost?
 

stxma

Well-Known Member
1 Oct 2008
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A: SAMUEL RIG TERMS - FIX 13

Edit I mean = Transfer-Sort

When I say points are lost I mean ...

Suppose that after (study and selection) we came to what we see
that all games will be Ace = point 1
Then logically the sum 105 would consist of 14 aces and the sum
105 will take positions from 1 to 14 positions.

Then a sum of 105 gives only one column.

Now any sum greater than 105 will be given by which columns
a little out of 14 aces ... that is, the initial and only the starting sum
The higher the price, the fewer aces or vice versa
case the first 14 points that will have a sum of 105.
 

stxma

Well-Known Member
1 Oct 2008
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A: SAMUEL RIG TERMS - FIX 13

In this table with a sum of 105-220

How many aces will be kept?

We said that they will start from 14 since we have an initial sum of 105

When the sum will reach 220 points = 1
will they have remained?
 
Last edited:

Kentribet

Member
4 Feb 2012
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A: SAMUEL RIG TERMS - FIX 13

In this table with a sum of 105-220

How many aces will be kept?

We said that they will start from 14 since we have an initial sum of 105

When the sum will reach 220 points = 1
will they have remained?

First of all, the painting needs correction. There is 42 twice

I repeat, the numbers from 1-42 are EVALUATION of the matches and result from the conversion of the percentages played by the points 1-X-2 for each match. It has been written above about it.

With your own evaluation and editing in a program (match 11 was corrected as 1 -> 11, X -> 29, 2 -> 41- I think there is no more mistake)
the result for the range 105-220 is 151.532 accepted columns and the sort with the winning column of 14 aces (so all YOUR first points) has

1 -> 14
28 -> 13ARIA
364 -> 12ARIA
2912 -> 11ARIA
15692 -> 10ARIA
45370 -> 9ARIA
58037 -> 8ARIA
26580 -> 7ARIA
2548 -> 6ARIA.

If people understood this table theory,
then I would continue to post it on the site.

Good luck (because a lot of Jack Pot was collected).
 
Last edited:

Kentribet

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A: SAMUEL RIG TERMS - FIX 13

I should also add that playing a sum of 220 exactly,
then YOUR final columns are 8.038

The sorting with N.S. 14 aces says

90 columns with 10 hits
1426 with 9
3091 with 8
2959 with 7
472 to 6.

So with a "dry" sum we have a dispersion of B.S.
 

snoopjohn

New Member
22 Jan 2012
29
11
3
A: SAMUEL RIG TERMS - FIX 13

In this table with a sum of 105-220

How many aces will be kept?

We said that they will start from 14 since we have an initial sum of 105

When the sum will reach 220 points = 1
will they have remained?


bro you give limits 220 to 220 and you put another basic next to it and you count the aces from 10 to 14, if it counts you 0 columns there is no column with 10 aces in the limits 220 - up to 220. then you put limits 9 to 9 on the base and you see how many columns expensive there are with 9 aces, and so on.
it is very simple to find everything with the right construction program.
 

snoopjohn

New Member
22 Jan 2012
29
11
3
A: SAMUEL RIG TERMS - FIX 13

I should also add that playing a sum of 220 exactly,
then YOUR final columns are 8.038

The sorting with N.S. 14 aces says

90 columns with 10 hits
1426 with 9
3091 with 8
2959 with 7
472 to 6.

So with a "dry" sum we have a dispersion of B.S.

there is a mistake here, because you do not have to have the same result every time (you only have to divide the numbers normally with first second and third points).
to point out the following.

Another can put the following in a match: 5 in the ace 32 in the x and 40 in the double. which in my opinion for the table to play correctly you have to put from 1 to 14 matches 1,2,3,4 to 14 (the main column), 14 to 28 in another 14 matches as second points (there should be no 2 numbers from 14 to 28 in a match), and the third points from 29 to 42. Because the stxma he simply did not distribute them, but mixed them up wherever he went. and has made a mistake,. has given the numbers 1 the numbers 1-16-23, which logically means that the ace is the first favorite of the card and, the second best point is the x of the card, and one of the best doubles of the card! χοαοχοχοα
if you have logically chosen this ace as your favorite, you can not have both the x and the double favorite, because they will play you in too many columns.
logically if it was a game of 70-20-10 in proportion to the odds you had to put 1-28-42, if it was the grand favorite of the card.
in a race now where everything would be shared you had to give the price
7-20-35 although I have some reservations because the points would not play with the same chances.
I personally do not like this painting.
 
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stxma

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1 Oct 2008
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A: SAMUEL RIG TERMS - FIX 13

there is something wrong here,
has given the numbers 1 the numbers 1-16-23, which logically means that the ace is the first favorite of the card and, the second best point is the x of the card, and one of the best doubles of the card! χοαοχοχοα

You probably did not understand the function of the table here

The panel works vertically only and not horizontally
It is not of the type ............... 70-20-10
Does not combine sharing (first ... second ,,, third point)
It evaluates 42 points
That is, which point we see first ........ which fifteenth ...... and which
in descending order up to 42
snoopjohn whoa whoa
 
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