Good evening to all members!
Because I'm completely scrapped in terms of senioritytwis mathematically and on the occasion of a discussion I had yesterday with a friend who has been involved in roulette, I wanted to ask anyone who knows or if they can calculate the chances of the colors coming to roulette as follows:
k-m-k-m-k-m-k-m-k-m-k-m-k-m
k: red m: black
That is, to come 14 times alternately, with the probability of 0 of course always lurking.
For continuous colors red or black we know that 10-12 consecutive can come for fun.
Because I'm completely scrapped in terms of senioritytwis mathematically and on the occasion of a discussion I had yesterday with a friend who has been involved in roulette, I wanted to ask anyone who knows or if they can calculate the chances of the colors coming to roulette as follows:
k-m-k-m-k-m-k-m-k-m-k-m-k-m
k: red m: black
That is, to come 14 times alternately, with the probability of 0 of course always lurking.
For continuous colors red or black we know that 10-12 consecutive can come for fun.